ext_40518 ([identity profile] a-musing-amazon.livejournal.com) wrote in [personal profile] lovingboth 2009-04-22 05:54 pm (UTC)

My full response was in the comments: which in addition to lots of example depending on what type of number was allowed also gave what I thought was the general complex number solution a+bi x 120/(a+bi), a+bi <>0.

Though of course 120/(a+bi) is not expresed in standard complex form which would, I think, be 120a/(a^2+b^2) - 120b/(a^2+b^2)i.

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